Hello,
I am trying to set up a mixed linux win2k environment.
I have up an running a backhand enabled linux whith apache 1.3.28.
Next I have installed the ntbhb program on a win2k machine.
Configured in regedit and starting in a dos box.
I get the result:
>$ bhBrodcast -run
> Broadcasting mod_backhand ...
> Hit enter ...
Viewing in registry I see a entry Arriba whith a reasonable value
However calling /backhand/ on my linux system doesn't show me the w2k
system.
My configuration is :
- on linux/apache :
------------------------
<IfModule mod_backhand.c>
UnixSocketDir /var/backhand/backhand
MulticastStats 192.168.69.255:4445
AcceptStats 192.168.69.0/24
</IfModule>
-----------------------
ifconfig eth0 shows :
eth0 Protokoll:Ethernet Hardware Adresse 00:08...
inet Adresse:192.168.69.98 Bcast:192.168.69.255
Maske:255.255.255.0
inet6 Adresse: fe80::208:c7ff:...
Gültigkeitsbereich:Verbindung
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:17015 errors:0 dropped:0 overruns:0 frame:0
TX packets:16127 errors:0 dropped:0 overruns:0 carrier:0
Kollisionen:1 Sendewarteschlangenlänge:100
RX bytes:3213952 (3.0 Mb) TX bytes:1492411 (1.4 Mb)
Interrupt:5 Basisadresse:0x4000
The registry on the w2k (IP 192.168.69.97)
is (don't know how to export in a readable way )
----------------------------------------------------------------
CerebraSoft Standard REG_SZ
|
- Backhand_Broadcast Standard REG_SZ
| Arriba REG_DWORD 0x14...(336633000)
|
- BH WIN01 (Standard) REG_SZ
ContactIP REG_SZ 192.168.69.97
ContactPort REG_SZ 80
HostName REG_SZ win 01
SendIP REG_SZ 192.168.69.255
--------------------------------------------------------------------
The w2k is running a apache too (whithout mod_backhand! do I need it there
??).
And the w2k machine is running as vmware client with the linux system as a
host !
So, where are the w2k broadcasts going ?
Greetings
Rolf Schaufelberger
I am trying to set up a mixed linux win2k environment.
I have up an running a backhand enabled linux whith apache 1.3.28.
Next I have installed the ntbhb program on a win2k machine.
Configured in regedit and starting in a dos box.
I get the result:
>$ bhBrodcast -run
> Broadcasting mod_backhand ...
> Hit enter ...
Viewing in registry I see a entry Arriba whith a reasonable value
However calling /backhand/ on my linux system doesn't show me the w2k
system.
My configuration is :
- on linux/apache :
------------------------
<IfModule mod_backhand.c>
UnixSocketDir /var/backhand/backhand
MulticastStats 192.168.69.255:4445
AcceptStats 192.168.69.0/24
</IfModule>
-----------------------
ifconfig eth0 shows :
eth0 Protokoll:Ethernet Hardware Adresse 00:08...
inet Adresse:192.168.69.98 Bcast:192.168.69.255
Maske:255.255.255.0
inet6 Adresse: fe80::208:c7ff:...
Gültigkeitsbereich:Verbindung
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:17015 errors:0 dropped:0 overruns:0 frame:0
TX packets:16127 errors:0 dropped:0 overruns:0 carrier:0
Kollisionen:1 Sendewarteschlangenlänge:100
RX bytes:3213952 (3.0 Mb) TX bytes:1492411 (1.4 Mb)
Interrupt:5 Basisadresse:0x4000
The registry on the w2k (IP 192.168.69.97)
is (don't know how to export in a readable way )
----------------------------------------------------------------
CerebraSoft Standard REG_SZ
|
- Backhand_Broadcast Standard REG_SZ
| Arriba REG_DWORD 0x14...(336633000)
|
- BH WIN01 (Standard) REG_SZ
ContactIP REG_SZ 192.168.69.97
ContactPort REG_SZ 80
HostName REG_SZ win 01
SendIP REG_SZ 192.168.69.255
--------------------------------------------------------------------
The w2k is running a apache too (whithout mod_backhand! do I need it there
??).
And the w2k machine is running as vmware client with the linux system as a
host !
So, where are the w2k broadcasts going ?
Greetings
Rolf Schaufelberger