Mailing List Archive

[Bug 1519] zlib version check is fake in the configure script. installation failure.
https://bugzilla.mindrot.org/show_bug.cgi?id=1519


Damien Miller <djm@mindrot.org> changed:

What |Removed |Added
----------------------------------------------------------------------------
CC| |djm@mindrot.org




--- Comment #1 from Damien Miller <djm@mindrot.org> 2008-09-01 20:22:58 ---
Your analysis is incorrect - the test for $zlib_check_nonfatal checks
whether it is blank or not. An unset shell variable is equivalent to a
blank one, so this is fine.

I'm not sure I understand what your problem is: are you saying that
configure misdetects your zlib as too old? If so you will need to
provide more information, such as the version of zlib you have
installed and the generated config.log.

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[Bug 1519] zlib version check is fake in the configure script. installation failure. [ In reply to ]
https://bugzilla.mindrot.org/show_bug.cgi?id=1519


Rod B. <re.bmgr@gmail.com> changed:

What |Removed |Added
----------------------------------------------------------------------------
Status|NEW |RESOLVED
Resolution| |INVALID




--- Comment #2 from Rod B. <re.bmgr@gmail.com> 2008-09-01 20:58:48 ---
Ok, I try to explain the problem.

The point is that the configure script misdetects my non-local zlib
version.

I have zlib version 1.2.3 installed /usr/lib /lib /usr/include
and I have zlib version 1.2.1 in /usr/local/lib /usr/local/include

Sorry for reporting it as a bug but the version detected by the
configure script
is version 1.2.1. I have just taken off /usr/local/include/zlib.h and
the configure
script works perfectly.

Is that normal that the configure script checks a local version in
/usr/local/include/zlib.h against the root system-wide version in
/usr/include/zlib.h ?
It must be my mistake with my environment definition.

I am sorry I haven't seen the full "if" condition line 10696 of the
configure script
which certainly needs some smarter indentation.

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