I'm having trouble accessing a calling script from a called script at run
time.
Here is an example:
#first file, will call second
from Tkinter import *
import tkFileDialog, string
root = None
def importScript():
filename = tkFileDialog.askopenfilename()
if filename != '':
list = string.split(filename, '/')
filename = list[-1]
#dir = string.join(list[:-1], '/')
#sys.path.append(dir)
exec "import %s" % filename[:-3]
if __name__ == "__main__": #?
root = Tk()
b = Button(root, text="import script", command=importScript)
b.pack()
root.mainloop()
#another file, picked by tkFileDialog at run time by user
from importTest import root
root.config(bg='green')
If I put the "if __name__ == '__main__':" in, the second file can't get at
the
root properly. If I leave it out, when I import root in the second file, it
creates
a new root window. How can I get at the root without making a new one?
Thanks,
John
time.
Here is an example:
#first file, will call second
from Tkinter import *
import tkFileDialog, string
root = None
def importScript():
filename = tkFileDialog.askopenfilename()
if filename != '':
list = string.split(filename, '/')
filename = list[-1]
#dir = string.join(list[:-1], '/')
#sys.path.append(dir)
exec "import %s" % filename[:-3]
if __name__ == "__main__": #?
root = Tk()
b = Button(root, text="import script", command=importScript)
b.pack()
root.mainloop()
#another file, picked by tkFileDialog at run time by user
from importTest import root
root.config(bg='green')
If I put the "if __name__ == '__main__':" in, the second file can't get at
the
root properly. If I leave it out, when I import root in the second file, it
creates
a new root window. How can I get at the root without making a new one?
Thanks,
John