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Why not:

>>> l = [1, 3, 5, 9, 2, 7]
>>> l.index(max(l))
3
>>> l.index(min(l))
0

On Tue, 2021-08-31 at 21:25 -0700, ABCCDE921 wrote:
> I dont want to import numpy
>
> argmax(list)
>    returns index of (left most) max element
>
>  argmin(list)
>    returns index of (left most) min element

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Because that does 2 passes over the entire array when you only need one and there is no option to specify if you want the leftmost or rightmost element


On Wednesday, September 1, 2021 at 12:02:29 PM UTC+5:30, Paul Bryan wrote:
> Why not:
>
> >>> l = [1, 3, 5, 9, 2, 7]
> >>> l.index(max(l))
> 3
> >>> l.index(min(l))
> 0
> On Tue, 2021-08-31 at 21:25 -0700, ABCCDE921 wrote:
> > I dont want to import numpy
> >
> > argmax(list)
> > returns index of (left most) max element
> >
> > argmin(list)
> > returns index of (left most) min element
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On 01/09/2021 06:25, ABCCDE921 wrote:
> I dont want to import numpy
>
> argmax(list)
> returns index of (left most) max element


>>> import operator
>>> second = operator.itemgetter(1)
>>> def argmax(values):
return max(enumerate(values), key=second)[0]

>>> argmax([1, 2, 3, 0])
2

> argmin(list)
> returns index of (left most) min element

This is left as an exercise;)



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If only there were a library that already provides exactly the functions
you're asking for... ????

On Wed, Sep 1, 2021 at 9:54 AM ABCCDE921 <atharvasakhala5445@gmail.com>
wrote:

> Because that does 2 passes over the entire array when you only need one
> and there is no option to specify if you want the leftmost or rightmost
> element
>
>
> On Wednesday, September 1, 2021 at 12:02:29 PM UTC+5:30, Paul Bryan wrote:
> > Why not:
> >
> > >>> l = [1, 3, 5, 9, 2, 7]
> > >>> l.index(max(l))
> > 3
> > >>> l.index(min(l))
> > 0
> > On Tue, 2021-08-31 at 21:25 -0700, ABCCDE921 wrote:
> > > I dont want to import numpy
> > >
> > > argmax(list)
> > > returns index of (left most) max element
> > >
> > > argmin(list)
> > > returns index of (left most) min element
> --
> https://mail.python.org/mailman/listinfo/python-list
>
>

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How about this?:

python3 -c 'list_ = [1, 3, 5, 4, 2]; am = max((value, index) for index,
value in enumerate(list_)); print(am)'


On Wed, Sep 1, 2021 at 6:51 AM ABCCDE921 <atharvasakhala5445@gmail.com>
wrote:

> Because that does 2 passes over the entire array when you only need one
> and there is no option to specify if you want the leftmost or rightmost
> element
>
>
> On Wednesday, September 1, 2021 at 12:02:29 PM UTC+5:30, Paul Bryan wrote:
> > Why not:
> >
> > >>> l = [1, 3, 5, 9, 2, 7]
> > >>> l.index(max(l))
> > 3
> > >>> l.index(min(l))
> > 0
> > On Tue, 2021-08-31 at 21:25 -0700, ABCCDE921 wrote:
> > > I dont want to import numpy
> > >
> > > argmax(list)
> > > returns index of (left most) max element
> > >
> > > argmin(list)
> > > returns index of (left most) min element
> --
> https://mail.python.org/mailman/listinfo/python-list
>
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