Mailing List Archive

I would use path_info.
See Apache2::RequestRec manual page.

Regards,
Jacques

On 2022/04/21 12:21, Henrik S wrote:
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed.  and there is a handler setup for
> this path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.

I ended up writing something custom to do that.

On Wed, Apr 20, 2022 at 11:22 PM Henrik S <henrik@tomatoservers.com> wrote:

> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed. and there is a handler setup for this
> path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.
>


--
John Dunlap
*CTO | Lariat *

*Direct:*
*john@lariat.co <john@lariat.co>*

*Customer Service:*
877.268.6667
support@lariat.co

I sent this 8 years ago but, at the time, no one was interested.
[image: image.png]


On Thu, Apr 21, 2022 at 9:40 AM John Dunlap <John@lariat.co> wrote:

> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S <henrik@tomatoservers.com>
> wrote:
>
>> given the sample url:
>>
>> /api/user/id
>>
>> the part of "/api/user" is fixed. and there is a handler setup for this
>> path.
>>
>> how to get the id part in mod_perl?
>>
>> in other framework I could get it with the similar format:
>>
>> /api/user/:id
>>
>> puts "hallo #{id}"
>>
>>
>> Thank you.
>>
>
>
> --
> John Dunlap
> *CTO | Lariat *
>
> *Direct:*
> *john@lariat.co <john@lariat.co>*
>
> *Customer Service:*
> 877.268.6667
> support@lariat.co
>


--
John Dunlap
*CTO | Lariat *

*Direct:*
*john@lariat.co <john@lariat.co>*

*Customer Service:*
877.268.6667
support@lariat.co

If you are looking to build a REST api with Apache mod_perl, you might
be interested in Net::API::REST (https://metacpan.org/pod/Net::API::REST)

Jacques

On 2022/04/21 23:27, John Dunlap wrote:
> I sent this 8 years ago but, at the time, no one was interested.
> image.png
>
>
> On Thu, Apr 21, 2022 at 9:40 AM John Dunlap <John@lariat.co> wrote:
>
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S
> <henrik@tomatoservers.com> wrote:
>
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed.  and there is a handler
> setup for this
> path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.
>
>
>
> --
> John Dunlap
> /CTO | Lariat/
> /
> /
> /*Direct:*/
> /john@lariat.co/
> /
> *Customer Service:*/
> 877.268.6667
> support@lariat.co
>
>
>
> --
> John Dunlap
> /CTO | Lariat/
> /
> /
> /*Direct:*/
> /john@lariat.co/
> /
> *Customer Service:*/
> 877.268.6667
> support@lariat.co

(Sorry for the late reply, been out of town)

Recognizing that I've never gone as indepth with mod_perl as other
users, but it seems to me that accessing "id" here would just be a
matter of grabbing the PATH_INFO environment variable, wouldn't it?

if the url is www.example.com/app/user/12345, then the program is
/app/user, and $ENV{'PATH_INFO'} would contain /12345.  Chop off the
leading forward slash and you've got your ID.

Note that you'd have to have PerlSetupEnv on (the default, although I
think many may turn it off).

Or am I completely missing something?

Michael

On 4/21/22 6:40 AM, John Dunlap wrote:
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S <henrik@tomatoservers.com
> <mailto:henrik@tomatoservers.com>> wrote:
>
> given the sample url:
>
> /api/user/id
>
> the part of "/api/user" is fixed.  and there is a handler setup
> for this
> path.
>
> how to get the id part in mod_perl?
>
> in other framework I could get it with the similar format:
>
> /api/user/:id
>
> puts "hallo #{id}"
>
>
> Thank you.
>
>
>
> --
> John Dunlap
> /CTO | Lariat/
> /
> /
> /*Direct:*/
> /john@lariat.co <mailto:john@lariat.co>/
> /
> *Customer Service:*/
> 877.268.6667
> support@lariat.co <mailto:support@lariat.co>

You still have $r->path just pull the id from it ?

On Thu, May 5, 2022, 4:20 PM Michael A. Capone <mcapone@cablewholesale.com>
wrote:

> (Sorry for the late reply, been out of town)
>
> Recognizing that I've never gone as indepth with mod_perl as other users,
> but it seems to me that accessing "id" here would just be a matter of
> grabbing the PATH_INFO environment variable, wouldn't it?
>
> if the url is www.example.com/app/user/12345, then the program is
> /app/user, and $ENV{'PATH_INFO'} would contain /12345. Chop off the
> leading forward slash and you've got your ID.
>
> Note that you'd have to have PerlSetupEnv on (the default, although I
> think many may turn it off).
>
> Or am I completely missing something?
>
> Michael
>
> On 4/21/22 6:40 AM, John Dunlap wrote:
>
> I ended up writing something custom to do that.
>
> On Wed, Apr 20, 2022 at 11:22 PM Henrik S <henrik@tomatoservers.com>
> wrote:
>
>> given the sample url:
>>
>> /api/user/id
>>
>> the part of "/api/user" is fixed. and there is a handler setup for this
>> path.
>>
>> how to get the id part in mod_perl?
>>
>> in other framework I could get it with the similar format:
>>
>> /api/user/:id
>>
>> puts "hallo #{id}"
>>
>>
>> Thank you.
>>
>
>
> --
> John Dunlap
> *CTO | Lariat *
>
> *Direct:*
> *john@lariat.co <john@lariat.co>*
>
> * Customer Service:*
> 877.268.6667
> support@lariat.co
>
>
>